The Post method

This method will look in the Request object to see if there are any posted files. If so, it will loop over the files and create them on the server side. The server will return a 201 HttpStatus and a list of strings that will contain the full path of the file(s) at server side. When there are no files posted, the service will return a 401 status a.k.a. BadRequest.

public HttpResponseMessage Post()
       {
           HttpResponseMessage result = null;
           var httpRequest = HttpContext.Current.Request;

           // Check if files are available
           if (httpRequest.Files.Count > 0)
           {
               var files = new List<string>();

               // interate the files and save on the server
               foreach (string file in httpRequest.Files)
               {
                   var postedFile = httpRequest.Files[file];
                   var filePath = HttpContext.Current.Server.MapPath("~/" + postedFile.FileName);
                   postedFile.SaveAs( filePath);

                   files.Add(filePath);
               }

               // return result
              result = Request.CreateResponse(HttpStatusCode.Created, files);
           }
           else
           {
               // return BadRequest (no file(s) available)
               result = Request.CreateResponse(HttpStatusCode.BadRequest);
           }

           return result;
       }

The Get Method

As mentioned before, the Get Method will accept a string file that will identify (= filename) the file that needs to be downloaded.

public HttpResponseMessage Get(string id)
       {
           HttpResponseMessage result = null;
           var localFilePath = HttpContext.Current.Server.MapPath("~/" + id);

           // check if parameter is valid
           if (String.IsNullOrEmpty(id))
           {
               result = Request.CreateResponse(HttpStatusCode.BadRequest);
           }
               // check if file exists on the server
           else if (!File.Exists(localFilePath))
           {
               result = Request.CreateResponse(HttpStatusCode.Gone);
           }
           else
           {// serve the file to the client
               result = Request.CreateResponse( HttpStatusCode.OK);
               result.Content = new StreamContent(new FileStream(localFilePath, FileMode.Open, FileAccess.Read));
               result.Content.Headers.ContentDisposition = new System.Net.Http.Headers.ContentDispositionHeaderValue("attachment");
               result.Content.Headers.ContentDisposition.FileName = id;
           }

           return result;
       }

Uploading a File

Using a submit  button

 <form name="form1" method="post" action="api/file" enctype="multipart/form-data">
    <div>
        <label>
            Using submit</label>
        <input name="myFile" type="file" />
    </div>
    <div>
        <input type="submit" value="Submit" />
    </div>
    </form>

Using JQuery

<form enctype="multipart/form-data">
    <label>
        Using JQuery</label>
    <input name="file" type="file" />
    <input type="button" id="Upload" value="Upload" />
    </form>

        <script type="text/javascript">
            $(function () {
                $('#Upload').click(function () {
                    var formData = new FormData($('form')[0]);
                    $.ajax({
                        url: 'api/file', 
                        type: 'POST',
                        // Form data
                        data: formData,
                        //Options to tell JQuery not to process data or worry about content-type
                        cache: false,
                        contentType: false,
                        processData: false
                    });
                });
            });
        </script>